An Easy Task

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 4088 Accepted Submission(s): 2327

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.

Each test case contains two positive integers Y and N(1<=N<=10000).

Output

For each test case, you should output the Nth leap year from year Y.

Sample Input

32005 251855 122004 10000

Sample Output

2108190443236

Hint

We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

Author

Ignatius.L

easy task并不easy 无奈不过不着急慢慢来在错误和失败中学到东西才是重要的

上代码

1 #include 
      
        2 using namespace std; 3 //int leapJudge(int); 4 int main(){ 5     int cont,sYear,pYear; 6      7     cin>>cont; 8     //while(cont--)//这个cont--还是谜一样的存在 ！while(i--)中i是有个初值的，每次循环i会减1，当i的值等于0的时候，循环就会终止！ 9     10     for(int i =0;i
       
        >sYear>>pYear;15         int leapcont = 0;  //！！！！！！重大错误就出现在这句 之前把他放在第一层循环外 也是脑子瓦特掉了 16             int j;        17             for(j=sYear;;j++){18                 if(leapcont==pYear) break;19                 if((j%4==0&&j%100!=0)|j%400==0)//去掉了判断函数 因为确实是没什么卵用20                      leapcont++;21             }22         cout<
        
         <
         
          33 //using namespace std;34 //35 //int main()36 //{37 //    int cases;//38 //    int k;39 //    cin>>cases;40 //    while(cases--)41 //    {42 //        int y,n;43 //        cin>>y>>n;44 //        int num=0;45 //        for(k=y;;k++)46 //        {47 //            if(num==n) break;48 //            //判断是不是闰年49 //            if(k%4==0 && k%100!=0 || k%400==0)50 //                num++;51 //        }52 //        cout<
          
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